The Modular Operator

Write a program that prints the numbers from 1 to 100. For multiples of 3, print "Fizz" instead of the number. For multiples of 5, print "Buzz". For numbers which are multiples of both 3 and 5, print "FizzBuzz".

This problem tests your understanding of the modular operator (%) and control flow. The key insight is that you need to handle the most specific condition (divisible by both 3 AND 5) correctly. Instead of checking divisibility by 15 first, you can build the output string incrementally — append "Fizz" if divisible by 3, then append "Buzz" if divisible by 5. This naturally produces "FizzBuzz" for multiples of both.

1. Loop through numbers 1 to 100. 2. For each number, initialize an empty string. 3. If the number is divisible by 3, append "Fizz" to the string. 4. If the number is divisible by 5, append "Buzz" to the string. 5. If the string is still empty (not divisible by 3 or 5), print the number itself. 6. Otherwise, print the constructed string.

- Checking divisibility by 3 before checking for both 3 and 5, which causes "FizzBuzz" cases to print only "Fizz" - Using elif instead of separate if statements when building the string incrementally - Forgetting that 0 % 3 == 0 is true, so starting from 0 instead of 1 gives an extra empty output

FizzBuzz is a classic interview warm-up that tests basic control flow and the modular operator. The string-building approach is more elegant than checking for 15 first, and it scales better if more conditions are added (e.g., "Jazz" for multiples of 7).